Lecture notes of Physics
The Vectors
Polaris Coordinates of a Vector
How can we represent a vector?
-We plot an arrow:
• the length proportional to magnitude of vector
• the line represents the vector direction
• the point represents the vector path

e.g.
we plot a vector with:
inclination p/6
direction:
upwards
path:
upwards
magnitude: 55 uu
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5
4
3
2
1 p/6
The Polaris Coordinates are
(magnitude, inclination)  (r, a)
e.g. (5, p/6)

Lecture notes of Physics
The Vectors
Cartesian Coordinate of a Vector
We can use the Cartesians Axes for represent a vector
e.g.
we plot the previous vector:
direction:
slope p/6
path:
upwards
magnitude: 5 u
y
(r·cos(a), r·sin(a))
r·sin(a)
a=p/6
O
We can write the vector as

v = ρ  cosa  ˆi  ρ  sina ˆj
x
r·cos(a)
The Cartesians Coordinates are
(x-coordinate, y-coordinate)  (x, y)
e.g. (r·cos(a), r·sin(a))
r·cos(a) and r·sin(a)
are known as Cartesian Components
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
Change of Coordinate: Cartesians  Polaris
Lecture notes of Physics
The Vectors
y
(r·cos(a), r·sin(a))
r·sin(a)
a=p/6
O
5
(x, y)
4
x
3
2
r·cos(a)
Cartesians Coordinates
1 p/6
(r, a)
Polaris Coordinates
ρ = x2  y2
From Cartesian to Polar  
x = r  cosa 
y = r  sin a 
 y
a = arctg  
x
  From Polar to Cartesian
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
Lecture notes of Physics
The Vectors
Calculation with Vectors
• Product with a scalar (k)


a = k b

b
k=3


a
a has the same direction and path as b and
magnitude of a is three times greater than the magnitude of b
if 0<k<1 the magnitude of a is smaller than the magnitude of b
if k<0 the path of a is the opposite of path of b

b
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k = -1 

a

Lecture notes of Physics
The Vectors
Calculation with Vectors
• Addition of vectors
  
s = a b

b
The Parallelogram Law

a

s

+
We calculate the magnitude of s with Carnot Theorem
a

s
s2 = a2 + b2 – 2ab cos(a)
N.B.
s
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is known
as
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We always have
s  a+ b
the Resultant of a and b

Lecture notes of Physics
The Vectors
Calculation with Vectors
y
• Addition of vectors, Cartesian Coordinates
  
s = a b

b

a
+
s·cos(a)

a·cos(a)
s·sin(a) O
a·sin(a)
b·cos(b)
x

s
b·sin(b)
We describe the vector sum s
by adding the components of a and b

s =  xa  xb iˆ   ya  yb  ˆj
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
Lecture notes of Physics
The Vectors
Calculation with Vectors
• difference between vectors
  
d = a b
  
d =b a

b
a

a

d

a
-

b

b

a
-
In both cases the
magnitude of d is
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d2 =Scientifico
a2 + b2 Europeo
– 2ab cos(a)
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


b
  
d = ab

a

b   
 d = ba
a
Proof
We describe vector
difference d by subtracting
the components of b of a 
  
d = a  b = xa  xb iˆ   ya  yb  ˆj
Lecture notes of Physics
The Vectors
Calculation with Vectors
Comparison between addition and difference of vectors
• Addition
  
s = ab
  
s = a b
• Difference
  
d = a b
magnitude of s is
a
s2
=
a2 +
b2 –
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Observe
Gualtiero Giovanazzi [email protected]
  
 d = a b
a
magnitude of d is
2ab cos(a)
s

b

b
a

a
d2 = a2 + b2 – 2ab cos(a)

d
the position of a angle

Lecture notes of Physics
The Vectors
Decomposition of a vector
 To decompose a vector v find two vectors v1, v2 in two prefixed
direction, whose sum is equal to vector v

v
a2

v2
O

v

v1
b2

v1
a1

v
c2
O

v2
b1

v2
 v d2
v2
O

v1
c1
O
d1
now from v we can draw two lines parallel to the axes
in every case we can write:

v = v1iˆ  v2 ˆj

v1 = v  cos(angle between v and 1st axis)

st
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v2 = [email protected]
v  sin(angle between v and 1 axis)
Gualtiero Giovanazzi

Lecture notes of Physics
The Vectors
1st
Decomposition of a vector: Examples
A body is hung to the ceiling with two different ropes. It forms angles a1, and a2
with the ropes.
What are the tensions of the ropes?
z2

T2
z2

T1

v2

v1

z1
z2

v
The vector of body weight is directed downwards
The vectors of tensions are direct toward the ropes
So we can recognize two particular direction: the
lines along the ropes
So we draw a system of reference with the AXES
parallel
to the ropes
and‘Rainerum’
ORIGINATING from
Liceo Scientifico
Europeo
the body
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z1
z1
z2
z
1
v1
O

v2
We can decompose v in directions z1,
z2 to find 2 vectors, v1 and v2, whose
sum is equal to v:
v = v1 + v2
We can observe that
T
1= -v1 and T2= -v2
Therefore v is balanced by the two
vectors T1, T2 tensions of ropes:

-v = T1 + T2
Lecture notes of Physics
The Vectors
Decomposition of a vector: Examples
2nd A body is sliding on an inclined plane.
 z2
v2

v2
z2
z2

v
1
v1

v
z1
a
z1

v2
What force pulls down the body?
z2
Vector v directed downwards is the
Force (or acceleration) of gravity

v1
z1

z1
Vector v1 directed parallel to the
plane is the active component of the
Force (or acceleration) of gravity
responsible of sliding of the body. It is
indicated by v//
v// = v · sin(a)
The vector of body weight is directed downwards
So we can recognize two particular direction:
the line along the plane and
the line they perpendicular to it
Therefore we draw a system of reference with
the AXES parallel and perpendicular to the
plane
We
canScientifico
decompose
v in directions
z1, z2 to find 2
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vectors,
v1 and
v2, whose
sum is equal to v:
v=v1+v2
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Giovanazzi
[email protected]
Vector v2 directed perpendicularly to
the plane is the component of the
Force (or acceleration) of gravity that
holds the body to the plane. It is
indicated by vperp

v perp = v · cos(a)

In this way we find the force that pulls
the body downwards. This is vector v1
Lecture notes of Physics
The Vectors
Decomposition of a vector: Examples
3rd How changes the velocity vector for a cannon-ball?
b2
a2

v

v
a
c2
b1
a1
We choose 3 positions and we study the
velocity vector v


v
We can recognize two particular direction:
horizontal shifting and vertical shifting
c1
Therefore we draw a Cartesian system of
reference with the AXES horizontal and
vertical
We can decompose v on directions 1, 2 for find 2 vectors, v1 v2, whose sum is equal to v:
v = v1 + v2
We can repeat this for every point of trajectory. The vectors v1 v2 are the velocity with
there the cannon-ball moves in horizontal (v1) and vertical (v2)
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So we find the force that pulls down

the body. It is the vector v1
Lecture notes of Physics
Return
The Vectors
• Proof
  
d = a b
 
 

d = a  b

-b
Difference between Vectors

a
-

a

b

+ -b

b 
 
d = a b

a
 
 

d = a b
Liceo Scientifico
‘Rainerum’d
WeEuropeo
can translate
Gualtiero Giovanazzi [email protected]
We can use only
the addition of vectors
and multiplication with a number
We can use the
parallelogram law
The vector d, difference a-b, is a
vector that
start from the arrow of b
and arrives at the arrow of a
Lecture notes of Physics
The Vectors
The
End

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Scarica

The Vectors