Fisica Generale - Alan Giambattista, Betty McCarty Richardson Chapter 23: Reflection and Refraction of Light •Huygens’s Principle •Reflection •Refraction •Total Internal Reflection •Polarization by Reflection •Formation of Images •Plane Mirrors •Spherical Mirrors •Thin Lenses Copyright © 2008 – The McGraw-Hill Companies s.r.l. 1 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.1 Huygens’s Principle A set of points with equal phase is called a wavefront. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 2 Fisica Generale - Alan Giambattista, Betty McCarty Richardson A ray points in the direction of wave propagation and is perpendicular to the wavefronts. Or a ray is a line in the direction along which light energy is flowing. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 3 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Huygens’s principle: At some time t, consider every point on a wavefront as a source of a new spherical wave. These wavelets move outward at the same speed as the original wave. At a later time t+t, each wavelet has a radius vt, where v is the speed of propagation of the wave. The wavefront at t+t is a surface tangent to the wavelets. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 4 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Geometric optics is an approximation to the behavior of light that applies when interference and diffraction are negligible. In order for diffraction to be negligible, the sizes of objects must be large compared to the wavelength of light. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 5 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.2 Reflection of Light When light is reflected from a smooth surface the rays incident at a given angle are reflected at the same angle. This is specular reflection. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 6 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Reflection from a rough surface is called diffuse reflection. “Smooth” and “rough” are determined based on the wavelength of the incident rays. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 7 Fisica Generale - Alan Giambattista, Betty McCarty Richardson The angle of incidence equals the angle of reflection. The incident ray, reflected ray, and normal all lie in the same plane. The incident ray and reflected ray are on opposite sides of the normal. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 8 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.3 Refraction of Light When light rays pass from one medium to another they change direction. This is called refraction. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 9 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Snell’s Law n1 sin 1 n2 sin 2 where the subscripts refer to the two different media. The angles are measured from the normal. When going from high n to low n, the ray will bend away from the normal. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 10 Fisica Generale - Alan Giambattista, Betty McCarty Richardson The incident ray, transmitted ray, and normal all lie in the same plane. The incident and transmitted rays are on opposite sides of the normal. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 11 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example (text problem 23.11): Sunlight strikes the surface of a lake. A diver sees the Sun at an angle of 42.0° with respect to the vertical. What angle do the Sun’s rays in air make with the vertical? incident wave 1 n1 = 1.00; air surface n2 = 1.33; water 42° Transmitted wave n1 sin 1 n2 sin 2 1.00sin 1 1.333sin 42 Normal sin 1 0.8920 1 63.1 Copyright © 2008 – The McGraw-Hill Companies s.r.l. 12 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.4 Total Internal Reflection The angle of incidence for when the angle of refraction is 90° is called the critical angle. n1 sin 1 n2 sin 2 n1 sin c n2 sin 90 n2 n2 sin c n1 Copyright © 2008 – The McGraw-Hill Companies s.r.l. 13 Fisica Generale - Alan Giambattista, Betty McCarty Richardson If the angle of incidence is greater than or equal to the critical angle, then no wave is transmitted into the other medium. The wave is completely reflected from the boundary. Total internal reflection can only occur when the incident medium has a larger index of refraction than the second medium. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 14 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example (text problem 23.22): Calculate the critical angle for sapphire surrounded by air. 2=90 n2 = 1.0; air n1 = 1.77; sapphire surface 1 incident wave Transmitted wave Normal n1 sin 1 n2 sin 2 1.77 sin c 1.00sin 90 sin c 0.565 1 34.4 Copyright © 2008 – The McGraw-Hill Companies s.r.l. 15 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.5 Polarization by Reflection Brewster’s angle is the angle of incidence for which the reflected light is completely polarized. Light is totally polarized when the reflected ray and the transmitted ray are perpendicular. ni sin i nt sin t ni sin B nt sin 90 B nt cos B nt tan B ni Copyright © 2008 – The McGraw-Hill Companies s.r.l. 16 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example (text problem 23.32): (a) Sunlight reflected from the still surface of a lake is totally polarized when the incident light is at what angle with respect to the horizontal? nwater 1.33 tan B 1.33 nair 1.00 B 53.1 The angle is measured from the normal, so 90 - 53.1 = 36.9 is the angle from the horizontal. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 17 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example continued: (b) In what direction is the reflected light polarized? It is polarized perpendicular to the plane of incidence. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 18 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example continued: (c) Is any light incident at this angle transmitted into the water? If so, at what angle below the horizontal does the transmitted light travel? From Snell’s Law: n1 sin 1 n2 sin 2 1.00sin 53.1 1.333sin 2 sin 2 0.6000 2 36.9 The angle is measured from the normal, so 90 - 36.9 = 53.1 is the angle from the horizontal. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 19 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.6 Formation of Images An image is real if light rays from a point on the object converge to a corresponding point on the image. A camera lens forms a real image. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 20 Fisica Generale - Alan Giambattista, Betty McCarty Richardson The light rays appear to come from behind the mirror. Your eye focuses the diverging rays reflected by the mirror. An image is virtual if the light rays from a point on the object are directed as if they diverged from a point on the image, even though the rays do not actually pass through the image point. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 21 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example (text problem 23.35): A defect in a diamond appears to be 2.00 mm below the surface when viewed from directly above that surface. How far beneath the surface is the defect. Air n2 =1.00 2 2 Surface Diamond n1 = 2.419 1 1 y’ y Actual location of defect Copyright © 2008 – The McGraw-Hill Companies s.r.l. 22 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example continued: The angles 1 and 2 are related by Snell’s Law: n1 sin 1 n2 sin 2 The actual depth of the defect is y and it appears to be at a depth of y’. These quantities are related by: y tan 2 y tan 1 Copyright © 2008 – The McGraw-Hill Companies s.r.l. 23 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example continued: Dividing the previous two expressions gives: n1 y cos1 n2 y cos2 As long as you are directly above the defect and its image, the angles 1 and 2 are nearly 0°. Rays from only a narrow range of angles will enter your eye. The above expression simplifies to: n1 y n2 y y n2 y n1 (general result) Copyright © 2008 – The McGraw-Hill Companies s.r.l. 24 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example continued: The actual depth of the defect in the diamond is then n1 2.419 y y 2.00 mm 4.84 mm. n2 1.00 Copyright © 2008 – The McGraw-Hill Companies s.r.l. 25 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.7 Plane Mirrors A point source and its image are at the same distance from the mirror, but on opposite sides of the mirror. Treat an extended object as a set of point sources. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 26 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example (text problem 23.41): Entering a darkened room, Gustav strikes a match in an attempt to see his surroundings. At once he sees what looks like another match about 4 m away from him. As it turns out, a mirror hangs on one of the walls. How far is Gustav from the wall with the mirror? The image seems 4 m away, but the mirror is only 2 m away since the rays will appear to come from a point 2 m behind the mirror. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 27 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.8 Spherical Mirrors vertex Center of curvature Principal axis The focal point A convex (or diverging) mirror curves away from the observer. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 28 Fisica Generale - Alan Giambattista, Betty McCarty Richardson A ray parallel to the principle axis is reflected, and it appears to have come from point F, the focal point of the mirror. For a convex mirror, the focal point is on the axis and is located a distance 0.5R behind the mirror, where R is the radius of curvature. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 29 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Drawn in green, red, and blue are the principal rays. 1. A ray parallel to the principal axis is reflected as if it came from the focal point. (green) 2. A ray along a radius is reflected back upon itself. (red) 3. A ray directed toward the focal point is reflected parallel to the principal axis. (blue) Copyright © 2008 – The McGraw-Hill Companies s.r.l. 30 Fisica Generale - Alan Giambattista, Betty McCarty Richardson For the pencil in the previous figure, the image is upright, virtual, smaller than the object, and closer to the mirror than the object. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 31 Fisica Generale - Alan Giambattista, Betty McCarty Richardson A concave (or converging) mirror curves toward the observer. Center of curvature vertex Principal axis The focal point Copyright © 2008 – The McGraw-Hill Companies s.r.l. 32 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Drawn in green, red, and blue are the principal rays. 1. A ray parallel to the principal axis is reflected through the focal point. (green) 2. A ray along a radius is reflected back upon itself. (red) 3. A ray along the direction from the focal point to the mirror is reflected parallel to the principal axis. (blue) Copyright © 2008 – The McGraw-Hill Companies s.r.l. 33 Fisica Generale - Alan Giambattista, Betty McCarty Richardson The magnification is defined as image size h m . object size h An inverted image has m<0 and an upright image has m>0. The expression for magnification can also be written as m q p where p is the object distance and q is the image distance. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 34 Fisica Generale - Alan Giambattista, Betty McCarty Richardson The mirror equation: 1 1 1 p q f where f is the focal length of the mirror. f<0 when the focal point is behind the mirror. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 35 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example (text problem 23.46): An object 2.00 cm high is placed 12.0 cm in front of a convex mirror with a radius of curvature of 8.00 cm. Where is the image formed? 1 1 1 p q f where p = 12.0 cm, f = -0.5R = -4.00 cm, and q is the unknown image distance. Solving gives q = -3.00 cm. The image is behind the mirror. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 36 Fisica Generale - Alan Giambattista, Betty McCarty Richardson §23.9 Thin Lenses A diverging lens will bend light away from the principle axis. A converging lens will bend light toward the principal axis. Copyright © 2008 – The McGraw-Hill Companies s.r.l. 37 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Copyright © 2008 – The McGraw-Hill Companies s.r.l. 38 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Magnification: h q m h p The thin lens equation: 1 1 1 p q f Copyright © 2008 – The McGraw-Hill Companies s.r.l. 39 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example (text problem 23.64): A diverging lens has a focal length -8.00 cm. (a) What are the image distances for objects placed at various distances from the lens? Is the image real or virtual? Upright or inverted? Enlarged or diminished? Object distance Image distance Real / virtual? Upright / inverted? Enlarged/ diminished 5 cm -3.08 cm Virtual upright Diminished 8 cm -4.00 cm Virtual upright Diminished 14 cm -5.09 cm Virtual upright Diminished 16 cm -5.33 cm Virtual upright Diminished 20 cm -5.71 cm Virtual upright Diminished Copyright © 2008 – The McGraw-Hill Companies s.r.l. 40 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Example continued: (b) If the object is 4.00 cm high, what is the height of the image? Object distance Image distance Magnification Image height 5 cm -3.08 cm 0.616 2.46 cm 8 cm -4.00 cm 0.500 2.00 cm 14 cm -5.09 cm 0.364 1.45 cm 16 cm -5.33 cm 0.333 1.33 cm 20 cm -5.71 cm 0.285 1.14 cm Copyright © 2008 – The McGraw-Hill Companies s.r.l. 41 Fisica Generale - Alan Giambattista, Betty McCarty Richardson Summary •The Laws of Reflection •The Laws of Refraction •Condition for Total Internal Reflection •Condition for Total Polarization of Reflected Light •Real/virtual Images •Mirrors (plane & spherical) •Thin Lenses Copyright © 2008 – The McGraw-Hill Companies s.r.l. 42